Applications of Derivatives: every key term you need (+ practice quiz)
40 flashcard terms for AP Calculus AB Unit 3, written to match the course framework. Read them here, drill them as flashcards, or take the 26-question quiz. Free, no account needed.
Visual representation of dy/dx at points (x,y); shows direction of solutions to differential equations.
Optimization with Constraints
Lagrange multipliers concept; use constraint to eliminate variable or solve system of equations from optimization conditions.
Mean Value Theorem Conclusion
If f is continuous on [a,b] and differentiable on (a,b), some c in (a,b) satisfies f'(c) = [f(b)-f(a)]/(b-a): an instantaneous rate equals the average rate.
When MVT Fails
|x| on [-1,1] has no c with f'(c) = 0 because differentiability fails at the interior point x = 0, so the hypotheses are not met.
First Derivative Test
At a critical point, a sign change of f' from positive to negative gives a local maximum; negative to positive gives a local minimum; no change gives neither.
Repeated Root in f'
A factor like (x-1)² in f' touches zero without changing sign, so x = 1 is a critical point that is not an extremum.
Second Derivative Test Limits
If f'(c) = 0 and f''(c) = 0, the test is inconclusive and the first derivative test or higher analysis must be used.
Inflection Points
Occur where f'' changes sign, not merely where f'' = 0; concavity must actually reverse for the point to qualify.
Candidates Test
On a closed interval, evaluate f at every critical point and at both endpoints; the largest and smallest values are the absolute extrema.
Optimization Workflow
Write the objective, use a constraint to reduce to one variable, state the domain, differentiate, and justify the extremum before answering in context.
Open-Top Box Result
Minimizing x² + 4xh subject to x²h = 32 gives surface area x² + 128/x, minimized at x = 4 with height 2.
Related Rates Setup
Write an equation relating the quantities first, differentiate with respect to time, and only then substitute the instantaneous values.
Ladder Problem
For x² + y² = L², differentiating gives x(dx/dt) + y(dy/dt) = 0, so the top slides down at rate -(x/y)(dx/dt).
Shadow and Similar Triangles
Proportions from similar triangles relate a walker's distance to the shadow-tip distance; differentiating that proportion gives the tip's speed.
Linear Approximation
L(x) = f(a) + f'(a)(x-a) estimates nearby values; concave-down curves make the estimate an overestimate, concave-up an underestimate.
L'Hôpital on 0/0
lim(x→0)(e^x - 1 - x)/x² = 1/2 after applying the rule twice; check the indeterminate form again before each application.
Speeding Up vs Slowing Down
An object speeds up when velocity and acceleration share a sign and slows down when their signs differ, regardless of direction of travel.
Reading a Graph of f'
Where the graph of f' is above the axis f increases; where f' increases f is concave up; x-intercepts of f' with sign change locate extrema of f.